How to Insert Select Option /Dropdown Value into database in PHP MySQL

By Super Admin | May 15, 2021 | PHP
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https://www.fundaofwebit.com/post/how-to-insert-select-option-value-in-database-using-php-mysql

How to Insert Select Option /Dropdown Value into database in PHP MySQL


In this article, you will learn about how to insert select option values in database using php mysql also know as insert drop down list values in php mysql. so, when you submit the form the dropdown list value will be sent to mysql query using POST method in php.

I have used Bootstrap v5 to design the user interface.

Lets get started: (how to insert dropdown value in database using php)

Note: For better and detailed understanding. please watch out the Video above.

Step 1: Create a table named demo into your Database (MySQL) as follows:

CREATE TABLE `demo` (
    `id` int(11NOT NULL,
    `name` varchar(191NOT NULL,
    `gender` varchar(20NOT NULL
);

Step 2: Create a index.php file and paste the below html form design code:

<?php session_start(); ?>
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Funda of Web IT</title>
    <link href="https://cdn.jsdelivr.net/npm/bootstrap@5.0.0-beta1/dist/css/bootstrap.min.css" rel="stylesheet">
</head>
<body>
    
    <div class="container">
        <div class="row justify-content-center">
            <div class="col-md-10">

                <?php 
                    if(isset($_SESSION['status']))
                    {
                        ?>
                            <div class="alert alert-warning alert-dismissible fade show" role="alert">
                            <strong>Hey!</strong> <?php echo $_SESSION['status']; ?>
                            <button type="button" class="btn-close" data-bs-dismiss="alert" aria-label="Close"></button>
                            </div>
                        <?php
                         unset($_SESSION['status']);
                    }
                ?>

                <div class="card mt-5">
                    <div class="card-header">
                        <h4>How to Insert Select Option value (Dropdown Box) into Database in php</h4>
                    </div>
                    <div class="card-body">

                        <form action="code.php" method="POST">
                            <div class="from-group mb-3">
                                <label for="">Name</label>
                                <input type="text" name="name" class="form-control" />
                            </div>
                            <div class="from-group mb-3">
                                <label for="">Gender</label>
                                <select name="gender" class="form-control">
                                    <option value="">--Select Gender--</option>
                                    <option value="Male">Male</option>
                                    <option value="Female">Female</option>
                                </select>
                            </div>
                            <div class="from-group mb-3">
                                <button type="submit" name="save_select" class="btn btn-primary">Save Selectbox</button>
                            </div>
                        </form>

                    </div>
                </div>
            </div>
        </div>
    </div>

    <script src="https://code.jquery.com/jquery-3.5.1.js"></script>
    <script src="https://cdn.jsdelivr.net/npm/bootstrap@5.0.0-beta1/dist/js/bootstrap.bundle.min.js"></script>
</body>
</html>

Now, when you click on the Submit button, the <form> contains action="code.php" so, lets go to Step 3 to write the code:

Step 3: Create a code.php file and paste the below code to insert dropdown list value in mysql database in php.

<?php
session_start();
$con = mysqli_connect("localhost","root","","phptutorials");

if(isset($_POST['save_select']))
{
    $name = $_POST['name'];
    $gender = $_POST['gender'];

    $query = "INSERT INTO demo (name,gender) VALUES ('$name','$gender')";
    $query_run = mysqli_query($con$query);

    if($query_run)
    {
        $_SESSION['status'] = "Inserted Succesfully";
        header("Location: index.php");
    }
    else
    {
        $_SESSION['status'] = "Not Inserted";
        header("Location: index.php");
    }
}
?>


Thanks for reading...